The correct decreasing order of basic strength is:
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Solution
As the size of central atom increases the lone pair of electrons occupies a larger volume. In other words electron density on the central atom decreases and consequently its tendency to donate a pair of electrons decreases along with basic character from NH3 to BiH3.
The solubility of silver bromide in hypo solution is due to the formation of :
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Solution
Hypo solution is Na2S2O3 solution which is used in photography for fixing films & prints. Photographic emulsions are made of AgBr. After developing, the film is put into hypo solution. This forms soluble complex with Ag.
Na2S2O3 + Ag Br \(\overset{Na_{2}S_{2}O_{3}}{\rightarrow}\) Na5[Ag(S2O3)3]
Which of the following represents correct sequence of decreasing acidic character of oxides?
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Solution
For oxides of same element higher the oxidation state,more will be acidic character.
\(\overset{+5}{N_{2}O_{5}}> \overset{+2}{NO}> \overset{+1}{N_{2}O}\)
The ease of liquefaction of noble gases increases in the order
In which one of the following oxides of nitrogen, one nitrogen atom is not directly linked to oxygen?
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Solution
In N2O (nitrous oxide) two N atoms are covalently bonded through triple bond[N = N → O]
In case of nitrogen, NCl3 is possible but not NCl5 while in case of phosphorus, PCl3 as well as PCl5 are possible. It is due to
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Solution
7N = 1s2 2s2 2p3; 15P = 1s2 2s2 2p6 3s2 3p3
In phosphorous the 3d- orbitals are available. Hence phosphorus can from pentahalides also but nitrogen cannot form pentahalide due to absence of d-orbitals
The p-block element that forms predominantly basic oxide is
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Solution
Bi forms basic oxides whereas N and P form acidic and As and Sb form amphoteric oxides.
Regarding F– and Cl– which of the following statements is/are correct?
(i)Cl– can giveup an electron more easily than F–
(ii)Cl– is a better reducing agent than F–
(iii)Cl– is smaller in size than F–
(iv)F– can be oxidized more readily than Cl–
When Br2 is treated with aqueous solutions of NaF,NaCl and NaI separately
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Solution
Br2 reacts with NaI only to get I2.
2NaI + Br2 → 2NaBr + I2
Which of the following bonds will be most polar?
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Solution
Polarity of the bond depends up on the electronegativity difference of the two atoms forming the bond. Greater the electronegativity difference, more is the polarity of the bond.
N – Cl O – F N– F N – N
3.0–3.0 3.5–4.0 3.0–4.0 3.0–3.0