When alumina is heated with carbon in the atmosphere of nitrogen then products formed are

Al + CO
Al + CO + N₂
Al + CO₂
AlN +CO

Solution

Solution

The shape of \(SO_{4}^{2-}\) ion is

square planar
tetrahedral
trigonal bipyramidal
hexagonal

Solution

\(SO_{4}^{2-}\)ion is tetrahedral since hybridization of S is sp³.

Solution

The compound having the lowest oxidation state of iron is:

K₄Fe(CN)₆
K₂FeO₄
Fe₂O₃
Fe(CO)₅

Solution

In Fe(CO)₅, Fe is in minimum oxidation state (zero).

The energy of electron in first energy level is -21.79 × 10^-12erg per atom. The energy of electron in second energy level is:

-54.47 × 10^-12erg atom^-1
-5.447 × 10^-12erg atom^-1
-0.5447 × 10^-12erg atom^-1
-0.05447 × 10^-12erg atom^-1

Solution

\({S_{E}}^{2}\)
\({S_{N}}^{1}\)
\({S_{N}}^{0}\)
\({S_{N}}^{2}\)

Solution

DIRECTION : These are Assertion-Reason type questions. Question contains two statements:Statement-1 (Assertion) and Statement-2 (Reason). Answer the question from the following four options.

Statement-1 :Mg continue to burn in nitric oxide
Statement-2 :During burning, heat evolved do not decompose NO.

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement -1
Statement-1 is True, Statement-2 is True ; Statement-2 is NOT a correct explanation for Statement-1
Statement-1 is True, Statement-2 is False
Statement-1 is False, Statement-2 is True

Solution

When Mg is burnt in nitric oxide, it continue to burn because during burning the heat evolved decompose NO to N₂ and O₂. Oxygen thus, produced helps Mg to burn.

Schottky defect defines imperfection in the lattice structure of

solid
gas
liquid
plasma

Solution

Schottky defects are found in solid.

Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl has pH 9.25.Then find out pK_b of NH₄OH

9.25
4.75
3.75
8.25

Solution

Cannizzaro reaction occurs with

CH₃-CH₂OH
C₆H₅CHO
CH₃CHO
CH₃-CO-CH₃

Solution

Cannizzaro reaction is given by aldehydes and ketones which do not have α-hydrogen atom. Benzaldehyde(C₆H₅CHO) does not have α-H atom and hencegives Cannizzaro reaction.

The O – O – H bond angle in H₂O₂ is

106°
109° 28'
120°
94.8°

Solution

O – O – H bond angle in H₂O₂ is 94.8°.

Which one of the following reactions of xenon compounds is not feasible?

3XeF₄ + 6H₂O → 2Xe + XeO₃ + 12HF + 1.5O₂
2XeF₂ + 2H₂O → 2Xe + 4HF +O₂
XeF₆ + RbF → Rb[XeF₇]
XeO₃ + 6HF → XeF₆ + 3HO

Solution

The products of the concerned reaction react each other forming back the reactants.

XeF₆ + 3H₂O → XeO₃ + 6HF

A piston filled with 0.04 mol of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constant temperature of 37.0ºC. As it does so, it absorbs 208 J of heat. The values of q and w for the process will be:(R = 8.314 J/mol K) (ln 7.5 = 2.01)

q= + 208 J, w = – 208 J
q = – 208 J, w =– 208 J
q= – 208 J, w = + 208 J
q= + 208 J, w = + 208 J

Solution

Process is isothermal reversible expansion,
hence ΔU = 0, therefore q = – W.Since q = +208 J, W= –208 J

The most suitable method for separation of a 1 : 1 mixture of ortho and para nitrophenols is

sublimation
chromatography
crystallization
steam distillation

Solution

The boiling point of o-nitrophenol is less than para-nitrophenol due to presence of intra molecular hydrogen bonding. Since p-nitrophenol is less volatile in steam than o-nitrophenolhence they can be separated by steam distillation.

Solution

An ideal gas can’t be liquefied because

its critical temperature is always above 0°C
Its molecules are relatively smaller in size
it solidifies before becoming a liquid
forces between its molecules are negligible

Solution

In the ideal gas, the inter molecular forces of attraction are negligible and hence it cannot be liquefied.

Philosopher’s wool on heating with BaO at 1100°C produces:

Ba + ZnCl₂
BaCdO₂
BaZnO₂
BaO₂ + Zn

Solution

Which of the following is combustion reaction?

C+O₂→CO₂
CH₄+O₂→CO₂+H₂O
Mg+O₂→MgO
all of these.

Solution

Combustion is heating of substance in excess of oxygen so as to form carbon bioxide and water.Sometimes water is not formed during combustion.

Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of A is 49 u. Molecular mass of B will be :

50.00 u
12.25 u
6.50 u
25.00 u

Solution

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