When a small amount of KMnO4is added to concentrated H2SO4, a green oily compound is obtained which is highly explosive in nature. Compound may be :
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Solution
KMnO2 reacts with H2SO4 to form Mn2O7 which is highly explosive substance.
2KMnO4+ H2SO4 → K2SO4+ Mn
2O7 + H2O
The correct name for NO2 using stock notation is :
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Solution
The method of representing oxidation number by a Roman numeral within the parenthesis represents Stock notation.
Which one of the following is not an allylic halide?
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Solution

DIRECTIONS: These are Assertion-Reason type questions. Question contains two statements:Statement-1 (Assertion) and Statement-2 (Reason). Answer these questions from the following four options.
Statement-1:In any ionic solid (MX) with Schottky defects,the number of positive and negative ions are same.
Statement-2 :Equal number of cation and anion vacancies are present
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Solution
Schottky defect is due to missing of equal number of cations and anions.
25.3 g of sodium carbonate, Na2CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ions,Na+ and carbonate ions, \(CO_{3}^{2-}\) are respectively (Molar mass of Na2CO3 = 106 g mol–1)
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Solution

Which of the following elements is present as the impurity to the maximum extent in the pig iron ?
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Solution
Pig iron or cast iron contains 3 –5% carbon and varying amounts of Mn,Si, P and S which makes the iron hard and brittle.
Which of the following pairs will form the most stable ionic bond?
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Solution
The stability of the ionic bond depends upon the lattice energy which is expected to be more between Mg and F due to +2 charge on Mg atom.
If the shortest wavelength of the spectral line of H-atom in the Lyman series is X,then the longest wavelength of the line in Balmer series of Li2+ is
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Solution

In which one of the following molecules the central atom said to adopt sp2 hybridization?
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Solution
BF3 involves sp2-hybridization.
Which of the following compounds is a good conductor of electricity in solution state ?
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Solution
Ionic compounds are dissociated in solution state and form ions. Ions are good carrier of charge which make solution conducting.
The stability of + 1 oxidation state increases in the sequence:
A metal salt solution forms a yellow precipitate with potassium chromate in acetic acid, a white precipitate with dil H2SO4, but gives no precipitate with NaCl. The metal salt solution will consist of
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PbCO3
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BaCO3
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MgCO3
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CaCO3
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Solution
BaCO3 forms a yellow ppt of barium chromate. BaCO3 forms a white precipitate of BaSO4. BaCl2 is soluble in water.
Which of the following is the best description for the behaviour of bromine in the reaction given below ?
H2O + Br2 → HOBr + HBr
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Proton acceptor only
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Both oxidized and reduced
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Oxidized only
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Reduced only
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Solution
\(H_{2}O+\overset{0}{Br_{2}}\rightarrow \overset{+1}{HOBr}+ \overset{-1}{HBr}\)
Thus here oxidation number of Br increases from 0 to+1 and also decreases from 0 to –1. Thus it is oxidised as well as reduced.
Which one of the following pairs of species have the same bond order?
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CN- and NO+
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CN- and CN+
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\(O_{2}^{-}\) and CN-
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NO+ and CN+
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Solution

Magnesium form Mg2+ and Mg+ because :
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ionic radius of Mg(II) is smaller than of Mg(I).
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hydration energy of divalent magnesium ion is higher.
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magnesium (II) carbonate is insoluble in water.
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generally higher oxidation states are preferred by metals.
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Solution
Statement (b) is correct.
Which of the following aqueous solution has minimum freezing point ?
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0.01 m NaCl
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0.005 m C2H5OH
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0.005 m MgI2
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0.005 m MgSO4
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Solution

Which one of the following orders of acid strength is correct?
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RCOOH > HC \(\equiv\) CH> HOH > ROH
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RCOOH > ROH > HOH > HC \(\equiv\) CH
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RCOOH > HOH > ROH > HC \(\equiv\) CH
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RCOOH > HOH > HC \(\equiv\) CH > ROH
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Solution
The higher is the tendency to donate proton, stronger is the acid. Thus the correct order is R – COOH > HOH > R – OH >CH \(\equiv\) CH depending upon the rate of donation of proton.
Which of the following carbonyls will have the strongest C – O bond ?
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[Mn (CO)6]+
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[Cr (CO)6]
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[V (CO)6]-
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[Fe (CO)5]
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Solution
As positive charge on the central metal atom increases,the less readily the metal can donate electron density into the π* orbitals of CO ligand (donation of electron density into π* orbitals of CO result in weakening of C – O bond). Hence, the C – O bond would be strongest in [Mn(CO)6]+.
The reason for almost doubling the rate of reaction on increasing the temperature of the reaction system by 10°C is
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The value of threshold energy increases
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Collision frequency increases
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The fraction of the molecule having energy equal to threshold energy or more increases
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Activation energy decreases
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Solution
When the temperature is increased, energy in form of heat is supplied which increases the kinetic energy of the reacting molecules. this will increase the number of collisions and ultimately the rate of reaction will be enhanced.
Schottky defect generally appears in :
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NaCl
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KCl
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CsCl
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all of these
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Solution
Schottky defect occurs in ionic crystals of type A+B,when equal number of cations and anions are missing from their lattice sites so that the electrical neutrality is maintained. This defect generally appears in highly ionic compounds which have high coordination number.NaCl, KCl and CsCl all have high coordination numbers i.e., 6, 6 and 8 respectively. So, Schottky defect appear in all of the given compounds.



