Which of the following is not an actinide ?
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Solution
Terbium is lanthanide as it belongs to 4f– series having configuration [Xe]4s96s2. However the remaining members belong to 5f– series (actinides).
The approximate percentage of iron in mischmetal is
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Solution
Mischmetal is an alloy which contains rare earth elements (94-95%), iron (5%) and traces of sulphur,carbon, silicon, calcium and aluminium. It is used in gas lighters, tracer bullets and shells.
Lanthanum is grouped with f-block elements because
The Ce (Z = 58) belongs to III rd group of periodic table.If it furnish one α particle to form an element ‘X’, then X belongs to
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Solution
58Ce is lanthanide. Lanthanides are from 57 to 71 all present in IIIrd group. Hence 58Ce forms 56X element on emission of one α particle with belongs to IInd group.
The titanium (atomic number 22) compound that does not exist is
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Solution
Oxidation state of Ti in the given compounds.as follows:
TiO – + 2
TiO2 – + 4
TiCl3 – + 3
K2TiF6 – + 4
K2TiO4 – + 6
The oxidation states exhibited by Ti is + 2, +3, + 4. So K2TiO4 does not exist.
For making Ag from AgNO3, which of the following is used
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Solution
When AgNO3 reacts with 3PH, then Ag is obtained.
\(\underset{silver\, nitrate}{6AgNO_{3}}+ \underset{phosphene} {2PH_{3}}\rightarrow 6Ag + \underset{phosphorous\, acid}{2H_{3}PO_{3}}+6NO_{2}\)
Which of the following factors may be regarded as the main cause of lanthanoide contraction?
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Solution
In lanthanides, there is poorer shielding of 5d electrons by 4 felectrons resulting in greater attraction of the nucleus over 5d electrons and contraction of the atomic radii.
Which of the following compounds is formed when a mixture of K2Cr2O7 and NaCl is heated with conc. H2SO4 ?
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Solution
K2Cr2O7 + 4KCl + 6H2SO4 \(\overset{Heat}{\rightarrow}\) 2CrO2Cl2 + 6KHSO4 + 3H2O
The radius of La3+(Atomic number of La = 57) is 1.06 Å.Which one of the following given values will be closest to the radius of Lu3+(Atomic number of Lu= 71) ?
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Solution
Aufbau principle does not give the correct arrangement of filling up of atomic orbitals in:
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Solution
Electronic configuration of Cr is [Ar] 3d54s1 because this gives it a stable half filled d5 configuration. Similarly,electronic configuration of Cu is [Ar]3d104s1. This filling of electrons is not in accordance with Aufbau principle.