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Calculate the wavelength (in nanometer) associated with a proton moving at 1.0 × 103 ms-1.(Mass of proton = 1.67 × 10-27 kg and h = 6.63 × 10-34 Js)
The total number of atomic orbitals in fourth energy level of an atom is :
Total no.of atomic orbitals in a shell = n2.
Given n = 4; Hence number of atomic orbitals in 4th shell will be 16.
Which of the following is not permissible arrangement of electrons in an atom?
m = –l to +l, through zero thus for l = 2, values of m will be – 2, –1, 0, +1, +2.Therefore for l = 2, m cannot have the value –3.
Maximum number of electrons in a subshell of an atom is determined by the following:
The number of sub shell is (2l + 1). The maximum number of electrons in the sub shell is 2(2l + 1) = (4l + 2)
The measurement of the electron position is associated with an uncertainty in momentum, which is equal to 1 × 10–18 g cm s–1.The uncertainty in electron velocity is, (mass of an electron is 9 × 10–28 g)
Δp = mΔv
Substituting the given values of Δx and m, we get
1 × 10-18g cm s-1 = 9 × 10-28g × Δv
or \(\Delta v = \frac{1 \times 10^{-18}}{9 \times 10^{-28}}\)
= 1.1 × 109cm s-1 ≅ 1 × 109 cm s-1
i.e. option (a) is correct.
An element M has an atomic mass 19 and atomic number 9, its ion is represented by
Atomic number 9 is for F and ion is F–.
The number of nodal planes ‘d’ orbital has
Number of nodal planes in d orbitals is 2.
An electron has principal quantum number 3. The number of its (i) subshells and (ii) orbitals would be respectively
The de Broglie wavelength associated with a ball of mass 200g and moving at a speed of 5 m/h, is of the order of (h = 6.625 × 10–34Js)
Which of the following represents correct set of the four quantum numbers for an electron in a 4d subshell ?