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When 10 g of a non-volatile solute is dissolved in 100 g of benzene, it raises boiling point by 1ºC then molecular mass of the solute is (Kb for benzene = 2.53 km-1)
Which of the following statements, regarding the mole fraction (x) of a component in solution, is incorrect?
2.5 litres of NaCl solution contain 5 moles of the solute.What is the molarity?
Molarity = \(\frac{No. of moles of solute}{Volume in litres}\) = \(\frac{}5{2.5}\) = 2M
If 0.44 gm of substance dissolved in 22.2 gm of benzene lowers the freezing point of benzene by 0.567ºC, then the molecular mass of substance is, the molal depression constant= 5.12ºC mol-1.
On adding a solute to a solvent having vapour pressure 0.80 atm, vapour pressure reduces to 0.60 atm. Mole fraction of solute is :
10g of NaCl is dissolved in 106g of the solution. Its concentration is :
An aqueous solution of glucose is 10% in strength. The volume in which 1 g mole of it is dissolved, will be :
The osmotic pressure at 17ºC of an aq. solution containing 1.75 gm of sucrose per 150 ml solution is :
The molarity of pure water is :
The vapour pressure of pure benzene at 25°C is 640 mm Hg and that of solution of solute A is 630 mm Hg. The molality of solution is –