CH₃Br + Nu^– CH₃ – Nu + Br^–
The decreasing order of the rate of the above reaction with nucleophiles (Nu^–) A to D is[Nu^– = (A) PhO^–, (B) AcO^–, (C) HO^–, (D) CH3O^–]

A> B > C > D
B> D > C > A
D> C> A > B
D> C > B > A

Solution

The stronger the acid, the weaker the conjugate base formed.
The acid character follows the order :
CH₃COOH > C₆H₅OH > H₂O > CH₃OH
The basic character will follow the order CH₃COO^- < C₆H₅O^- < ^-OH < CH₃O^-
Hence, decreasing order of rate of given reactions with
Nu^- is D > C >A > B

Which pair of isomerism is not possible together?

Ring-chain and functional
Geometrical and optical
Metamerism and functional
Metamerism and chain

Solution

Metamerism shown among compounds of the same functional group.

Geometrical
Optical
Both
None

Solution

Solution

Lone pair of electrons present on the nitrogen of benzyl amine is not involved in resonance.

In the anion HCOO^– the two carbon-oxygen bonds are found to be of equal length. what is the reason for it ?

The C = O bond is weaker than the C — O bond
The anion HCOO^– has two resonating structures
The anion is obtained by removal of a proton from the acid molecule
Electronic orbitals of carbon atom are hybridised

Solution

Which of the following is true regarding hyper conjugation,also known as no-bond resonance?
(i)Like inductive effect it involves donation of electrons through ?-bonds
(ii)Hyper conjugation involves overlapping of filled orbitals with the empty p orbital of the carbocation
(iii)Like resonance, it involves displacement of ? or lone pair of electrons to the carbon bearing positive charge
(iv)It involves delocalisation of ?- and ?- electrons

(ii) and (iv)
(ii)
(iii)
none

Solution

Which of the following is least reactive in a nucleophilic substitution reaction.

(CH₃)₃C-Cl
CH₂ = CHCl
CH₃ CH₂Cl
CH₂ = CHCH₂Cl

Solution

The correct order of reactivity towards the electrophilic substitution of the compounds aniline (I), benzene (II) and nitrobenzene (III) is

I > II > III
III > II > I
II > III >I
I < II > III

Solution

Correct order of stability is :

cis -2- butene > 1-butene > trans -2-butene
trans-2-butene > cis-2-butene > 1-butene
1-butene > cis-2-butene > trans-2- butene
cis-2-butene > trans-2-butene > 1-butene

Solution

Stability of an alkene depends upon the heat of hydrogenation of an alkene. The heat of hydration is the standard enthalpy change in hydrogenation of an alkene. The lower the heat of hydrogenation of analkene higher will be stability.
Order of stability Heat of hydrogenation(kJ/mol)
trans-2-butene– 115.5
cis-2-butene– 119.6 and
1-butene– 126.8 respectively.

Which of the following is false regarding a good contributor of a resonance hybrid?

It must have as many bonds as possible
It must have as many octets as possible
Negative charge, if any,should be on electronegative atom
None of the three

Solution

All statements are ture.

UnAttempted

0

Attempted

0

Correct

0

Wrong

0

Complete