NEET
Practice Test 3
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The alkene that will yield 2,3-dimethyl-2 butanol on hydration is :

  • Solution

    the only compound among the given options which gives 2, 3-dimethyl-2-butanol as shown in the table :

Which of the following reagents convert propene to 1-propanol?

  • Solution

In reaction sequence

molecule ‘M’ and reagent ‘R’ respectively are

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In the above sequence of reactions, B is

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1, 2-Dibromocyclohexane on dehydrobromination gives :

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The number of σ and π bonds in CH2= CH – CH = CH2

  • Solution

    As shown above, the given compound (1, 3-butadiene)contains 9σ and 2π bonds

The highest boiling point is expected for :

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    For isomeric alkanes,the one having longest straight chain has highest b.p. because of larger surface area.

In cyclopropane, cyclobutane and cyclohexane, the commongroup is

  • Solution

    correct answer is (d).

A hydrocarbon contains 10.5 g carbon and 1 g hydrogen. Its 0.36 g has 1 L volume at 1 atm and 127°C, hydrocarbon is :

  • Solution

    Sum of masses of C and H = 10.5 +1.0 =11.5

    %of C=\(\frac{10.5}{11.5}\times 100=91.3\)%

    %of H=\(\frac{1.0}{11.5}\times 100=8.7\)%

    Element % Ratio of atoms Simplest ratio
    C 91.3 91.3/12 = 7.61 7.61/7.61 = 1 × 7 = 7
    H 8.7 8.7/1= 8.7 8.7/7.61 = 1.14 × 7=8

    ∴Empirical formula = C7H8

    We know that n=PV⁄RT

    \(\frac{mass}{molar\: mass}=\frac{PV}{RT}\)

    \(\frac{2.81}{M}=\frac{1\times 1}{0.082\times 400};M=92.168\approx 92\)

    \(n=\frac{84+8}{92}=1\)

    ∴Molecular formula =(C7H8)×1=C7H8

When C2H2, CH4 and CH4 pass through a test tube which has ammonical Cu2Cl2, find out which gas comes out unaffected from test tube?

  • Solution

    C2H4 and CH4 will come out unaffected. C2H2 form scopper acetylide with ammonical

    Cu2Cl2+2NH4OH→Cu2O+H2O+2NH4Cl

    Cu2O+C2H2→Cu2C2+H2O

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