At 130°C, normal butane reacts with bromine, the product will be :
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Solution
The reaction of Br2 on alkane proceeds via free radical mechanism; 2° free radical is more stable than 1° free radical.Hence 2-bromobutane is major product.
For the preparation of t-butylmethyl ether which one of the following methods should be recommended?
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Solution
For the preparation of t-butylmethyl ether, the method described in option (c) should be recommended. It is due to the reasonthat alkoxides are not only nucleophiles but also strong bases. So, they tend to react with alkylhal ides by elimination to yield alkenes.Here the danger of competition between nucleophilic substitution and elimination reaction increases with the tendency of alkyl halides to under goelimination which follows the order 3° >2° > 1°.So,first of all we have to select 1° halide and obviously the second choice will be sodiumt-butoxide.
Also the method described in option (a) is not suitableas the ease of dehydration of alcohol follows the order 3° > 2° > 1°. So t-butanol will quickly give an alkene.
Aromatisation of n-hexane gives :
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Solution
CH2-CH2-CH2-CH2-CH2-CH3
Aromatisation is a process in which aromatic compounds are formed from open chain compounds.
Which types of isomerism isshown by 2, 3-dichlorobutane?
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Solution
2, 3-dichloro butane will exhibit optical isomerism due to the presence of two asymmetric carbon atom.
Which one of the following contain isopropyl group?
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Solution
It contains isopropyl group.
Of the five isomeric hexanes, the isomer which can give two monochlorinated compounds is
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Solution
Since it contains only two types ofH-atoms hence it will give only two monochlorinated compounds viz.
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Solution
2-Methylbutane on reacting with bromine in the presence of sunlight gives mainly
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Solution
Ease of replacement of H-atom 3° > 2° > 1°.
