DIRECTIONS: These are Assertion-Reason type question. Question contains two statements:Statement-1 (Assertion) and Statement-2 (Reason). Answer these questions from the following four options.
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Solution
(4n + 2)π electrons and planar structure are the essential conditions for aromaticity.
DIRECTIONS: These are Assertion-Reason type question. Question contains two statements:Statement-1 (Assertion) and Statement-2 (Reason). Answer these questions from the following four options.
Statement-1 :All the hydrogen atoms in CH2 = C = CH2 lie in one plane.
Statement-2 :Carbon atoms are sp2 and sp hybridized.
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Solution
The two hydrogen atoms on first carbon and the two H-atoms on the third carbon atom lie in perpendicular planes. The central carbon atom is sp-hybridized while terminal carbon atoms are sp2-hybridized.
DIRECTIONS: These are Assertion-Reason type question. Question contains two statements:Statement-1 (Assertion) and Statement-2 (Reason). Answer these questions from the following four options.
Statement-1 :Iodination of alkanes is reversible.
Statement-2 :Iodination is carried out in presence of iodicacid
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Solution
Iodination is reversible since formed HI is a strong reducing agent and reduces the alkyl iodide back to alkane.
CH4 + I2 ⇌ CH3I + HI
Iodination can be done only in presence of strong oxidising agents like iodic acid which destroys the hydriodic acid.
DIRECTIONS: These are Assertion-Reason type question. Question contains two statements:Statement-1 (Assertion) and Statement-2 (Reason). Answer these questions from the following four options.
Statement-1 :CH4 does not react with Cl2 in dark.
Statement-2 : Chlorination of CH4 takes place in sunlight.
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Solution
The assertion that chlorination of CH4 does not take place in dark is correct because it is a free radical reaction and free radicals are obtained in presence of sun light.
DIRECTIONS: These are Assertion-Reason type question. Question contains two statements:Statement-1 (Assertion) and Statement-2 (Reason). Answer these questions from the following four options.
Statement-1 :1-Butene on reaction with HBr in the presence of a peroxide produces 1-bromobutane.
Statement-2 :It involves the free radical mechanism
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Solution
In this reaction anti Markownikoff’s addition is explained on the basis of the fact that in the presence peroxides, addition takes place via free radical mechanism rather than the ionic mechanism.
DIRECTIONS: Read the passage given below and answer the question that follow :A hydrocarbon (X) of the formula C6H12 does not react with bromine water but react with bromine in presence of light, forming compound (Y). Compound (Y) on treatment with Alc. KOH gives compound [Z] which on ozonolysis gives (T) of the formula C6H10O2. Compound (T) reduces Tollens reagent and gives compound (W). (W) gives iodoform test and produce compound(U) which when heated with P2O5 forms a cyclic anhydride (V)
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Solution
DIRECTIONS: Read the passage given below and answer the question that follow :A hydrocarbon (X) of the formula C6H12 does not react with bromine water but react with bromine in presence of light, forming compound (Y). Compound (Y) on treatment with Alc. KOH gives compound [Z] which on ozonolysis gives (T) of the formula C6H10O2. Compound (T) reduces Tollens reagent and gives compound (W). (W) gives iodoform test and produce compound(U) which when heated with P2O5 forms a cyclic anhydride (V)
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Solution
2-Hexyne gives trans-2-Hexene on treatment with :
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Solution