Electron affinity is maximum for
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Solution
Electron affinity is energy released when electron is added to isolated gaseous atom. Its value decreases down the group. So electron affinity of F should be highest among halogens but due to its smaller size electron affinity of Cl is more than F.
∴ Cl has highest electron affinity.
Electron affinity is positive when :
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Solution
Electron affinity is said to be positive when an atom has spontaneous tendency to accept an electron. When O changes to O–, energy is released. So, this change has positive electron affinity while all other given changes required to be forced i.e., these require energy to occur.
A group 16 element exists in the monoatomic state in the metallic state. It also exists in two crystalline forms. The metal is
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Solution
Pollonium is only true metal in group 16. It has two crystalline forms ?-form which is cubic and ?-form which is rhombohedral.
Which one of the following represents the electronic configuration of the most electropositive element ?
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Solution
Electropositive nature increases down the group and decreases across the period.
The correct order of reactivity of halogens is
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Solution
We know that atomic no. of fluorine (F), chlorine (Cl)Bromine (Br) and Iodine (I) are 9, 17, 35 and 53 respectively. Therefore, correct order of reactivity of halogens is F >Cl > Br > I.
Eka-aluminium and EKa-silicon are known as
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Gallium and Germanium
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Aluminium and Silicon
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Iron and Sulphur
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Neutron and Magnesium
As per the modern periodic law,the physical and chemical properties of elements are periodic functions of their
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Atomic volume
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Electronic configuration
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Atomic weight
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Atomic size
Among the following options, the sequence of increasing first ionisation potential will be
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B< C< N
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B > C > N
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C< B< N
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N >C > B
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Solution
1st l.P. increases from left to right in a period.
Arrange S, P, As in order of increasing ionisation energy
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S < P< As
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P< S < As
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As < S < P
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As < P < S
Which ionisation potential (IP)in the following equations involves the greatest amount of energy ?
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Na → Na+ + e-
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k+ → k2+ + e-
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C2+ → C3+ + e-
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C+ → C2+ + e-
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Solution
k+ → k2 + e-. Since e –is to be removed from stable configuration.