Hydrogen bonding could not affect the boiling point of:

Solution

The compounds having O or F or N along with hydrogen show hydrogen bonding and have high boiling points. So HI does not form hydrogen bonds and its boiling point is not affected.

Which of the following does not contain any coordinate bond?

Solution

HF₂ is the only compound among the given options which does not contain any coordinate bond because it has hydrogen bonding.
[H – F•••H]–

In [Ag (CN₂)]^–, the number of π bonds is :

Solution

In one – C ≡ N, No. of π bonds = 2
So in [Ag (CN2)]^-,No. of π bonds
= 2×2 = 4

Among the following, the species having square planar geometry for central atom are
(i)XeF₄(ii)SF₄
(iii)[NiCl₄]^2-(iv)[PtCl₄]^2-

Which one of the following molecules will form a linear polymeric structure due to hydrogen bonding?

Which one of the following is the correct order of interactions?

Resonance structures can be written for

Solution

Resonating structures can be written only for such molecules in which multiple bonds are present, eg, O₃

Of the following hydrides which one has the lowest boiling point ?

Solution

NH₃ undergoes H-bonding and hence has the highest b.p. Among the remaining hydrides i.e. PH₃, AsH₃ and SbH₃ as we move from PH₃ to BiH₃, the molecular massincreases. As a result the van der waal’s forces of attraction increases and the boiling point increases regularly from PH₃ to BiH₃.

In the cyanide ion, the formal negative charge is on

Solution

In CN^- ion formal negative charge is on nitrogen atom due to lone pair of electrons.

Which of the following has the highest dipole moment?

Solution

Greater the difference in electronegativity between the two atoms, larger will be polarity and hence dipole moment. Thus (a) has maximum dipole moment.

Symmetrical molecules (µ = 0)

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