NEET

Solution

Solution

When gas is compressed its entropy decreases so, ?S is negative.

The maximum work which a system can perform at constant temperature and pressure equals

?H –?E
(– ?G)
q– ?E
P.?V –?G

Solution

Solution

Eq. (b) shows largest phase change i.e., gas ⟶ solid

Solution

eq. (i) + eq. (ii) find the required result and divide by 2.

Given the bond energies N = N,H – H and N– H bonds are 945,436 and 391 kJ mole–1 respectively, the enthalpy of the following reaction N₂(g) + 2H₂(g) ⟶ 2NH₃(g) is

–93 kJ
102 kJ
90 kJ
105 kJ

Solution

Work done during isothermal expansion of one mole of an ideal gas from 10 atm. to 1 atm. at 300 K is:

4938.8 joule
4138.8 joule
5744.1 joule
6257.2 joule

Solution

Heat of neutralization of strong acid against strong base is constant and is equal to

13.7 kcal
57.3 kJ
5.73 × 10⁴ J
All of the above

Solution

13.7 kcal = 57 kJ = 5.7 × 10⁴ J

How many joules of heat are absorbed when 70.0 grams of water is completely vaporised at its boiling point?

23,352
7,000
15,813
158, 200

Solution

If enthalpies of formation of C₂H₄(g), CO₂(g) and H₂O(l) at 25°C and 1 atm pressure are 52, – 394 and – 286 kJ/mol respectively, the change in enthalpy is equal to

– 141.2 kJ/mol
– 1412 kJ/mol
+ 14.2 kJ/mol
+ 1412 kJ/mol

Solution

UnAttempted

0

Attempted

0

Correct

0

Wrong

0

Complete

Attempted

Correct

UnAttempted

Wrong