NEET

An organic compound contains 49.3% carbon, 6.84% hydrogen and its vapour density is 73. Molecular formula of the compound is :

C₃H₅O₂
C₄H₁₀O₂
C₆H₁₀O₄
C₃H₁₀O₂

Solution

The empirical formula of an acid is CH₂O₂, the probable molecular formula of acid may be :

C₃H₆O₄
CH₂O
CH₂O₂
C₂H₄O₂

Solution

The acid with empirical formula CH₂O₂ is formic acid,H—COOH.

The simplest formula of a compound containing 50% of element X (atomic mass 10) and 50% of element Y (atomic mass 20) is

XY
XY₃
X₂Y
X₂Y₃

Solution

50% of X (Atomic mass 10), 50% of Y (Atomic mass 20).Relative number of atoms of X = \(\frac{50}{10}\) = 5 and than Y = \(\frac{50}{20}\) = 2.5

Simple Ratio 2 : 1. Formula X₂Y

In a compound C, Hand N atoms are present in 9: 1 : 3.5 by weight. Molecular weight of compound is 108. Molecular formula of compound is

C₂H₆N₂
C₃H₄N
C₆H₈N₂
C₉H₁₂N₃

Solution

Assuming fully decomposed, the volume of CO₂ released at STP on heating 9.85 g of BaCO₃(Atomic mass, Ba = 137) will be

2.24 L
4.96 L
1.12 L
0.84 L

Solution

In the reaction

4NH₃(g) + 5O₂(g) ⟶ 4NO(g) + 6H₂O(l)
When 1 mole of ammonia and 1 mole of O₂ are made to react to completion,

1.0 mole of H₂O is produced
1.0 mole of NO will be produced
all the oxygen will be consumed
all the ammonia will be consumed

Solution

Liquid benzene (C₆H₆) burns in oxygen according to the equation 2C₆H₆ (l) + 15O₂(g) ⟶ 12CO₂(g) 6H₂O(g).How many litres of O₂ at STP are needed to complete the combustion of 39 g of liquid benzene?(Mol. wt. of O₂ = 32,C₆H₆= 78)