At temperature 327°C and concentration C osmotic pressure of a solution is P, the same solution at concentration C/2 and at temperature 427°C shows osmotic pressure of 2 atm, value of P will be

\(\frac{12}{7}\)
\(\frac{24}{7}\)
\(\frac{6}{5}\)
\(\frac{5}{6}\)

Solution

The solution containing 4.0 gm of a polyvinyl chloride polymer in 1 litre of dioxane was found to have an osmotic pressure 6.0 × 10^-4 atmosphere at 300K, the value of R used is 0.082 litre atmosphere mole^-1 K^-1. The molecular mass of the polymer was found to be

3.0 × 10²
1.6 × 10⁵
5.6 × 10⁴
6.4 × 10²

Solution

Molarity of H₂SO₄ is 18 M. Its density is 1.8 g/ml. Hence molality is

Solution

The mole fraction of water in 20% aqueous solution (By weight) of H₂O₂ is

\(\frac{77}{68}\)
\(\frac{68}{77}\)
\(\frac{20}{80}\)
\(\frac{80}{20}\)

Solution

A solution of Al2(SO₄)₃ {d=1.253 gm / ml} contain 22% salt by weight. The molarity, normality and molality of the solution is

0.805 M, 4.83 N, 0.825 m
0.825 M, 48.3 N, 0.805 m
4.83 M, 4.83 N, 4.83 m
None of these

Solution

The volume of 4 N HCl and 10 N HCl required to make 1 litre of 6 NHCl are

0.75 litre of 10 N HCl and 0.25 litre of 4 N HCl
0.50 litre of 4N HCl and 0.50 litre of 10 N HCl
0.67 litre of 4 N HCl and 0.33 litre of 10 N HCl
0.80 litre of 4N HCl and 0.20 litre of 10 N HCl

Solution

N₁V₁ + N₂V₂ = NV
4x+ 10 (1– x) = 6 × 1; –6x = –4 ; x = 0.67
Thus 0.67 litre of 4N HCl
1 – x= 1– 0.67 = 0.33 litre of 10 N HCl

Which of the following has been arranged in the increasing order of freezing point?

0.025M KNO₃ < 0.1M NH₂CSNH₂ < 0.05M BaCl₂ < 0.1NaCl
0.1M NaCl < 0.05M BaCl₂ < 0.1M NH₂CSNH₂ < 0.025M KNO₃
0.1M NH₂CSNH₂ < 0.1M NaCl < 0.05M BaCl₂ < 0.025M KNO₃
0.025M KNO₃ < 0.05M BaCl₂ < 0.1M NaCl < 0.1M NH₂CSNH₂

Solution

Greater is the effective molarity (i× C), higher the ΔT_f value and lower the freezing point.

The freezing point of equimolal aqueous solutions will be highest for :

C₆H₅NH₃Cl (aniline hydrochloride)
Ca(NO₃)₂
La(NO₃)₃
C₆H₁₂O₆(glucose)

Solution

The salt that ionises to least extent will have highest freezing point. [ i.e., minimum ΔT_f ]

The osmotic pressure (at 27° C) of an aqueous solution(200mL) containing 6 g of a protein is 2 × 10^-3 atm. If R =0.080 L atm mol^-1 K^-1, the molecular weight of protein is

7.2 × 10⁵
3.6 × 10⁵
1.8 ×10⁵
1.0 × 10⁵

Solution

?1, ?2, ?3 and ?4 atm are the osmotic pressures of 5% (mass/volume) solutions of urea,fructose, sucrose and KCl respectively at certain temperature. The correct order of their magnitudes is :

?₁ > ?₄ > ?₂ > ?₃
?₁ < ?₄ < ?₂ < ?₃
?₄ > ?₁ > ?₂ > ?₃
?₄ > ?₁ > ?₃ > ?₂

Solution

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