NEET
Practice Test 6
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Which of the following is used for the conversion of 2-hexyne into trans-2-hexene ?

  • Solution

    H2/Pd/BaSO4 reduces an alkyne to cis-alkene, H2/Pt reduces it to alkane, NaBH4 does not reduce an alkyne.Reduction of an alkyne by active metal in liq. NH3 gives trans-alkene.

Which of the following species participate in sulphonation of benzene ring ?

  • Solution

    SO3 participates in sulphonation of benzene.

What is the product when acetylene reacts with hypochlorous acid?

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Which of these will not react with acetylene?

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A compound is treated with NaNH2 to give sodium salt.Identify the compound

  • Solution

    Only C2H2(acetylene)has acidic H-atoms and hence reacts with NaNH2 to form sodium salt, i.e.,HC ≡ CH + NaNH2 ⟶ HC ≡ CNa + NH3

Below, some catalysts and corresponding proceses/reactions are matched.The mismatch is :

  • Solution

    V2O5 is used as a catalyst in contact process for the manufacture of SO3 and hence H2SO4. In Haber-Bosch process for the manufacture of NH3, finely divided Fe+ molybdenum are used.

  • Solution

  • Solution

    Greater the s character of C, higher is its electronegativity, shorter and stronger will be the bond formed by it. Thus -C ≡ C- is the strongest bond.

The major product obtained on treatment of CH3CH2CH(F)CH3 with CH3O–/CH3OH is :

  • Solution

Which of the following gives propyne on hydrolysis?

  • Solution

    Mg2C3 gives propyne.

    Mg2C3 + 4H2O ⟶ 2Mg(OH)2 + CH3 - C = CH

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Hydrocarbons
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