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In the equation I2 + I– ⟶ \(I_{3}^{-}\), Lewis base is
I- is electron donor. Hence it is Lewis base.
Species acting as both Bronsted acid and base, is
(HSO4)- can accept and donate a proton
(HSO4)- + H+ ⇌ H2SO4 (acting as base)
(HSO4)- – H+ ⇌ SO42-. (acting as acid)
In which of the following cases, pH is greater than 7?
Which one of the following compounds is not a protonic acid?
B(OH)3 does not provide H+ions in water instead it accepts OH– ion and hence it is Lewis acid.
B(OH)3 + H2O ⇌ [B(OH)4]- + H+
Solution of 0.1 N NH4OH and 0.1 N NH4Cl has pH 9.25.Then find out pKb of NH4OH
A base when dissolved in water yields a solution with ahydroxyl ion concentration of 0.05 mol litre-1. The solution is
Given :Hydroxyl ion concentration
[OH–] = 0.05 mol L–1.
We know that
[H+][OH–] = 1 × 10-14
Le chatelier principle is not applicable to solid-solid equilibrium.
Solubility product of a salt AB is 1 × 10–8 in a solution in which the concentration of A+ions is 10–3M. The salt will precipitate when the concentration of B–ions is kept
H2O(g) ⇌ H2(g) + 1/2O2(g)
In this reaction volume is increasing in the forward direction. So on increasing temperature reaction will proceed in forward direction
The reaction A + B ⇌ C + D + heat, has reached equilibrium. The reaction may be made to proceed forward by
Exothermic reaction is favoured by low temperature to proceed in forward direction.