Practice Test 4 Archives

When an electron is removed from an atom, its energy

increases
decreases
remains the same
none of these

Solution

Energy is supplied in order to remove electron from atoms. So energy of atom increases when electron is removed from atom.

Ionic radii of

Ti⁴⁺ < Mn²⁺
³⁵Cl^- < ³⁷Cl^-
K⁺ > Cl^-1
P³⁺ > P⁵⁺

Solution

P⁵⁺ has more effective nuclear charge and smaller size than P³⁺.

Chloride ion and potassium ion are isoelectronic. Then

their sizes are same
Cl^–ion is bigger than K⁺ ion
K⁺ ion is relatively bigger
their sizes depend on either cation or anion

First ionization potential will be maximum for

uranium
hydrogen
lithium
iron

Solution

Due to presence of most penetrating s-electron,hydrogen (1s) shows maximum IP out of list

The correct order of radii is

N < Be
F^-O^2- N^3-
N< Li < K
Fe³⁺ Fe⁴⁺ Fe²⁺

The first ionisation potential in electron volts of nitrogen and oxygen atoms are respectively given by

14.6, 13.6
13.6, 14.6
13.6, 13.6
14.6, 14.6

Solution

Ionisation potential of nitrogen is more than that of oxygen. This is because nitrogen has more stable half-filled p-orbitals.(N = 1s², 2s², 2p³, O = 1s², 2s², 2p⁴)

An element having electronic configuration 1s², 2s² 2p⁶, 3s²3p¹ will form

neutral oxide
acidic oxide
basic oxide
amphoteric oxide

Solution

The given electronic configuration represents that it has 3 valency electrons or it can shows a maximum oxidation state of +3 and element with intermediate oxidation states form amphoteric oxides.

Which one of the following ions has the highest value of ionic radius ?

O^2–
B³⁺
Li⁺
F^–

Solution

O^–– and F^– are isoelectronic.Hence have same number of shells, therefore greater the nuclear charge smaller will be the size i.e.,O^{– –} > F–further Li⁺ and B³⁺ are isoelectronic. therefore Li⁺ > B³⁺ Hence the correct order of atomic size is.O^-- > F^– > Li⁺ > B³⁺

Correct order of first IP among following elements Be, B, C,N, O is

B< Be < C
B
Be

Be < B < C < O < N

Solution

Be – 1s²2s²; B – 1s²2s²2p¹; C – 1s²2s²2p²; N – 1s²2s²2p³;O – 1s²2s²2p⁴. IP increases along the period. But IP of Be >B. Further IP of O < N because atoms with fully or partly filled orbitals are most stable and hence have high ionisation energy.

Maximum ionisation potential is of :

Ca

Na

Be

Mg

Solution

Ionisation potential is amount of energy required to take outermost loosly bonded electron from isolated gaseous atom. Its value decreases in a group and increases along a period. Thus, here Be has highest ionisation potential.

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