NEET
Practice Test 10
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The number of anti-bonding electron pairs in \(O_{2}^{2-}\) molecularion on the basis of molecular orbital theory is, (Atomic number of O is 8)

  • Solution

Main axis of a diatomic molecule is z, molecular orbital px and py overlap to form which of the following orbital?

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    For π-overlap the lobes of the atomic orbitals are perpendicular to the line joining the nuclei.

Linear combination of two hybridized orbitals belonging to two atoms and each having one electron leads to a

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    Linear combination of two hybridized orbitals leads to the formation of sigma bond.

Which statement is NOT correct ?

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Each carbon in carbon suboxide (C3O2) is

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    O = C = C = C = O is sp hybridised.

Which one has a pyramidal structure

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    NH3 has pyramidal structure, as nitrogen is sp3 hybridised. This is due to the presence of lone pair of electrons on N atom.

The largest bond angle is in

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The shape of \(SO_{4}^{2-}\) ion is

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    \(SO_{4}^{2-}\)ion is tetrahedral since hybridization of S is sp3.

Which has the least bond angle

  • Solution

    H2O, NH3 and CH4 all are sp3 hybridized due to lp – lp repulsions, bond angle in H2O (104.5°) is lower than in NH3(107°)which have one lp and CH4(109° 28’) which have no lp BeF2 on the other hand, has sp hybridization and hence has a bond angle of 180°.

In the following molecule, the two carbon atoms marked by asterisk(*) possess the following type of hybridized orbitals H3C – C* ≣ C* – CH3

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Chemical Bonding And Molecular Structure
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