In the reaction :
\(C_{6}H_{5}CHO + C_{6}H_{5}NH_{2} \rightarrow C_{6}H_{5}N= CHC_{6}H_{5} + H_{2}O\) The compound, C₆H₅N = CHC₆H₅ is known as

aldol
Schiff’s base
Schiff’s reagent
Benedict’s reagent

Solution

What will be the final product in the following reaction sequence –
\(CH_{3}CH_{2}CN \overset{H^{+} / H_{2}O}{\rightarrow} A \overset{NH_{3}}{\rightarrow} B \overset{NaOBr}{\rightarrow} C\)

CH₃CH₂CONH₂
CH₃CH₂COBr
CH₃CH₂NH₂
CH₃CH₂CH₂NH₂

Solution

Ethyl isocyanide on hydrolysis in acidic medium generates

propanoic acid and ammonium salt
ethanoic acid and ammonium salt
methylamine salt and ethanoic acid
ethylamine salt and methanoic acid

Solution

Consider the following sequence of reactions :
\(Compound[A] \overset{Reduction}{\rightarrow} B \overset{HNO_{2}}{\rightarrow} CH_{3}CH_{2}OH\) The compound [A] is

CH₃CH₂CN
CH₃NO₂
CH₃NC
CH₃CN

Solution

\(C_{2}H_{5}NH_{2} + CS_{2} \overset{HgCl_{2}}{\rightarrow} C_{2}H_{5}NCS + HgS + 2HCl\) the above reaction is:

Libermann’s nitroso reaction
Carbylamine reaction
Hinsberg’s reaction
Hoffmann mustard oil reaction

Solution

The reaction is known as Hoffmann’s mustard oil reaction.

Which is formed, when acetonitrile is hydrolysed partially with cold concentrated HCl?

Acetic acid
Acetamide
Methyl cyanide
Acetic an hydrides

Solution

Nitration of aniline also gives m-nitro aniline, in strong acidic medium because

in electrophilic substitution reaction amino group is meta directing
inspite of substituents nitro group always goes tom-position
in strong acidic medium, nitration of aniline is a nucleophilic substitution reaction
in strong acidic medium aniline present as anilinium ion

Solution

Benzene diazonium chloride reacts with hypophosphorous acid to produce:

phenol
benzene
p-hydroxyazobenzene
benzonitrile

Solution

\(C_{2}H_{5}N_{2}Cl + H_{3}PO_{2} + H_{2}O \rightarrow C_{6}H_{6} + N_{2} + HCl + H_{3}PO_{3}\)

A primary amine is formed an amide by the treatment of bromine and alkali. The primary amine has :

1 carbon atom less than amide
1 carbon atom more than amide
1 hydrogen atom less than amide
1 hydrogen atom more than amide

Solution

Among the following, the strongest base is

C₆H₅NH₂
p– NO₂C₆H₄NH₂
m– NO₂ C₆H₄NH₂
C₆H₅CH₂NH₂

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