Three blocks of masses m1, m2 and m3 are connected by mass less strings, as shown, on a friction less table. They are pulled with a force T3 = 40 N. If m1 = 10 kg, m2= 6 kg and m3 = 4kg, the tension T2 will be
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Solution
The linear momentum p of a body moving in one dimension varies with time according to the equating P = a + bt2 where a and b are positive constants. The net force acting on the body is
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Solution
Linear momentum, P = a + bt2
dp⁄dt = 2bt(on differentiation)
∴ Rate of change of momentum, dp⁄dt ∝ t
By 2nd law of motion, dp⁄dt ∝ F
∴ F ∝ t
Two pulley arrangements of figure given are identical. The mass of the rope is negligible. In fig (a), the mass m is lifted by attaching a mass 2m to the other end of the rope. In fig(b), m is lifted up by pulling the other end of the rope with a constant downward force F =2mg. The acceleration of m in the two cases are respectively
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Solution
Let a and a' be the accelerations in both cases respectively. Then for fig (a),
T – mg = ma … (1)
and 2mg – T = 2ma … (2)
Adding (1) and (2), we get
mg = 3ma
∴ a = g⁄3
For fig (b),
T' - mg = ma' … (3)
and 2mg - T' = 0 … (4)
Solving (3) and (4)
a' = g
∴ a = g⁄3 and a' = g
When the road is dry and the coefficient of the friction is μ,the maximum speed of a car in a circular path is 10 ms-1. If the road becomes wet and μ’=μ⁄2, what is the maximum speed permitted?
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Solution
vmax=\(\sqrt{\mu gr}\)
A person with his hand in his pocket is skating on ice at the rate of 10m/s and describes a circle of radius 50 m. What is his inclination to vertical :(g = 10 m/sec2)
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Solution
Since surface (ice) is friction less, so the centripetal force required for skating will be provided by inclination of boy with the vertical and that angle is given as
tan θ=v2⁄rg where v is speed of skating & r is radius of circle in which he moves.
A small sphere is attached to a cord and rotates in a vertical circle about a point O. If the average speed of the sphere is increased, the cord is most likely to break at the orientation when them ass is at
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Solution
A circular road of radius r in which maximum velocity is v,has angle of banking
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Solution
From figure,
N sin θ=mv2⁄r....... (i)
N cos θ= mg...... (ii)
Dividing, we get
tan θ=v2⁄rg or θ=tan-1(v2⁄rg)
A cane filled with water is revolved in a vertical circle of radius 4 meter and the water just does not fall down. The time period of revolution will be
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Solution
A bucket tied at the end of a 1.6 m long string is whirled in a vertical circle with constant speed. What should be the minimum speed so that the water from the bucket does not spill when the bucket is at the highest position?
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Solution
The coefficient of friction between the rubber tyres and the road way is 0.25. The maximum speed with which a car can be driven round a curve of radius 20 m without skidding is(g = 9.8 m/s2)
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Solution