DIRECTION: Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-

(a) Statement-1 is true, Statement-2 is true; Statement -2 is a correct explanation for Statement-1

(b) Statement-1 is true, Statement-2 is true; Statement -2 is NOT a correct explanation for Statement-1

(d) Statement-1 is false, Statement-2 is true

Statement-1 :When a conductor is placed in an external electrostatic field, the net electric field inside the conductor becomes zero after a small instant of time.

Statement-2 :It is not possible to set up an electric field inside a conductor.

View Ans & Explanation
(c) Statement-1 is true, Statement-2 is false

Statement-1 is correct. The induced field cancels the external field. Statement-2 is false. When a current is setup in a conductor, there exists an electric field inside it.

DIRECTION: Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-

(a) Statement-1 is true, Statement-2 is true; Statement -2 is a correct explanation for Statement-1

(b) Statement-1 is true, Statement-2 is true; Statement -2 is NOT a correct explanation for Statement-1

(d) Statement-1 is false, Statement-2 is true

Statement-1 :A uniformly charged disc has a pin hole at its centre.The electric field at the centre of the disc is zero.

Statement-2 :Disc can be supposed to be made up of many rings. Also electric field at the centre of uniformly charged ring is zero

View Ans & Explanation
(a) Statement-1 is true, Statement-2 is true; Statement -2 is a correct explanation for Statement-1

The electric field due to disc is superposition of electric field due to its constituent ring as given in statement-2.Statement-1 is true, statement-2 is true, statement-2 is a correct explanation for statement-1.

DIRECTION: Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-

(a) Statement-1 is true, Statement-2 is true; Statement -2 is a correct explanation for Statement-1

(b) Statement-1 is true, Statement-2 is true; Statement -2 is NOT a correct explanation for Statement-1

(d) Statement-1 is false, Statement-2 is true

Statement-1 :The positive charge particle is placed in front of as pherical uncharged conductor. The number of lines of forces terminating on the sphere will be more than those emerging from it.

Statement-2 : The surface charge density at a point on the sphere nearest to the point charge will be negative and maximum in magnitude compared to other points on the sphere.

View Ans & Explanation
(d) Statement-1 is false, Statement-2 is true

No. of lines entering the surface = No. of lines leaving the surface.

DIRECTION: Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-

(a) Statement-1 is true, Statement-2 is true; Statement -2 is a correct explanation for Statement-1

(b) Statement-1 is true, Statement-2 is true; Statement -2 is NOT a correct explanation for Statement-1

(d) Statement-1 is false, Statement-2 is true

Statement-1 : Four point charges q₁, q₂, q₃ and q₄ are as shown in figure. The flux over the shown Gaussian surface depends only on charges q₁ and q₂.

Statement-2 : Electric field at all points on Gaussian surface depends only on charges q₁ and q₂.

View Ans & Explanation
(c) Statement-1 is true, Statement-2 is false

Electric field at any point depends on presence of all charges.

DIRECTION: Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-

(a) Statement-1 is true, Statement-2 is true; Statement -2 is a correct explanation for Statement-1

(b) Statement-1 is true, Statement-2 is true; Statement -2 is NOT a correct explanation for Statement-1

(d) Statement-1 is false, Statement-2 is true

Statement-1 :A deuteron and an a-particle are placed in an electric field. If F₁ and F₂ be the forces acting on them and a₁ and a₂ be their accelerations respectively then,a₁= a₂.

Statement-2 : Forces will be same in electric field.

View Ans & Explanation
(c) Statement-1 is true, Statement-2 is false

DIRECTION: Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-

(a) Statement-1 is true, Statement-2 is true; Statement -2 is a correct explanation for Statement-1

(b) Statement-1 is true, Statement-2 is true; Statement -2 is NOT a correct explanation for Statement-1

(d) Statement-1 is false, Statement-2 is true

Statement-1 : Consider two identical charges placed distance 2d apart, along x-axis.

The equilibrium of a positive test charge placed at the point O midway between them is stable for displacements along the x-axis.

Statement-2: Force on test charge is zero.

View Ans & Explanation
(b) Statement-1 is true, Statement-2 is true; Statement -2 is NOT a correct explanation for Statement-1

If +ve charge is displaced along x-axis, then net force will always act in a direction opposite to that of displacement and the test charge will always comeback to its original position.

Two pith balls carrying equal charges are suspended from a common point by strings of equal length. The equilibrium separation between them is r. Now the strings are rigidly clamped at half the height. The equilibrium separation between the balls now become

$\left ( \frac{r}{\sqrt[3]{2}} \right )$
$\left ( \frac{2r}{\sqrt{3}} \right )$
$\left ( \frac{2r}{3} \right )$
$\left ( \frac{r}{\sqrt{2}} \right )^{2}$

Solution

An electric dipole of moment ´p´ is placed in an electric field of intensity ´E´. The dipole acquires a position such that the axis of the dipole makes an angle θ with the direction of the field. Assuming that the potential energy of the dipole to be zero when =90°, the torque and the potential energy of the dipole will respectively be

p E sin θ, – p E cos θ
p E sin θ, –2 p E cos θ
p E sin θ, 2 p E cos θ
p E cos θ, – p E cos θ

Solution

The torque on the dipole is given as

τ = PE sin θ

The potential energy of the dipole in the electric field is given as

U = – PE cos θ

Two metallic spheres of radii 1 cm and 3 cm are given charges of –1 × 10^–2 C and 5 × 10^–2 C, respectively. If these are connected by a conducting wire, the final charge on the bigger sphere is

2 × 10^–2C
3 × 10^–2 C
4 × 10^–2C
1 × 10^–2 C

Solution

Three charges, each +q, are placed at the corners of an isosceles triangle ABC of sides BC and AC, 2a.D and E are the mid points of BC and CA. The work done in taking a charge Q from D to E is

$\frac{3qQ}{8\pi \varepsilon _{0}a}$
$\frac{qQ}{4\pi \varepsilon _{0}a}$
zero
$\frac{3qQ}{4\pi \varepsilon _{0}a}$

Solution

AC = BC

V_D= V_E

We have,

W = Q (V_E– V_D)

⇒ W = 0

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