Four resistors are connected as shown in fig. A 6 V battery of negligible resistance is connected across terminal AC.The potential difference across terminals B, D will be

0 V
1.5 V
2 V
3 V

Solution

The given figure is a circuit of balanced Wheatstone’s bridge. Point B and D would be at the same potential i.e., potential difference between these points is zero.

Each of the resistance in the network shown in fig. is equal to R. The resistance between the terminals A and B is

Solution

To get maximum current in a resistance of 3 ohms, one can use n rows of m cells (connected in series) connected in parallel. If the total number of cells is 24 and the internal resistance of a cell is 0.5 ohms then

m= 12, n =2
m= 8, n = 3
m= 2, n = 12
m= 6, n = 4

Solution

In an experiment to measure the internal resistance of a cell,by a potentiometer, it is found that the balance point is at a length of 2 m, when the cell is shunted by a 5 Ω resistance and is at a length of 3 m when the cell is shunted by a 10 Ω resistance. The internal resistance of the cell is then

1.5 Ω
10 Ω
15 Ω
1 Ω

Solution

An electrical cable of copper has just one wire of radius 9mm. Its resistance is 5ohm. This single copper wire of the cable is replaced by 6 different well insulated copper wire seach of radius 3 mm. The total resistance of the cable will now be equal to

7.5 ohm
45 ohm
90 ohm
270 ohm

Solution

The electrochemical equivalent of a metal is 3.3 × 10^–7 kg per coulomb. The mass of the metal liberated at the cathode when a 3 A current is passed for 2 seconds will be

19.8 × 10^–7kg
9.9 × 10^–7kg
6.6 × 10^–7kg
1.1 × 10^–7kg

Solution

m = ZIt.

A wire of radius r and another wire of radius 2r, both of same material and length are connected in series to each other. The combination is connected across a battery. The ratio of the heats produced in the two wires will be

4.00
2.00
0.50
0.25

Solution

Three equal resistors, connected across a source of e.m.f.together dissipate 10 watt of power. What will be the power dissipated in watts if the same resistors are connected in parallel across the same source of e.m.f.

10
10/3
30
90

Solution

(Hint : P = V²/R)

If nealy 10⁵ coulomb are liberated by 1gm equivalent of aluminium, then amount of aluminium (equivalent weight 9)deposited through electrolysis in 20 minutes by a current of 50 ampere will be :

0.6 gm.
0.09 gm
5.4 gm
10.8 gm

Solution

(Hint : m = Z it, where Z is electro chemical equivalent)

If current flowing in a conductor changes by 1% then power consumed will change by

10%
2%
1%
100%

Solution

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