A 60 volt battery would spend 1200 watt power across a resistance of :

Five resistance, each of 5 Ω, are connected as shown in figure.Find the equivalent resistance between points (1) A and B, (2) A and C.

A potentiometer is connected between A and B and the balance point is obtained at 203.6 cm. When the end of the potentiometer connected to B is shifted to C,then the balance point is obtained at 24.6cm. If now the potentiometer be connected between B and C, the balance point will be at:

The resistance of the four arms P, Q, R and S in a Wheatstone’s bridge are 10 ohm, 30 ohm, 30 ohm and 90 ohm, respectively.The e.m.f. and internal resistance of the cell are 7 volt and 5 ohm respectively. If the galvanometer resistance is 50 ohm, the current drawn from the cell will be

A wire of resistance 4 Wis stretched to twice its original length. The resistance of stretched wire would be

If voltage across a bulb rated 220 Volt-100 Watt drops by 2.5% of its rated value, the percentage of the rated value by which the power would decrease is

In the circuit shown the cells A and B have negligible resistances. For V_A= 12V, R₁= 500Ω and R= 100Ω the galvanometer (G) shows no deflection.The value of V_B is

A milli voltmeter of 25 milli volt range is to be converted into an ammeter of 25 ampere range. The value (in ohm) of necessary shunt will be

Cell having an emf ε and internal resistance r is connected across a variable external resistance R. As the resistance R is increased, the plot of potential difference V across R is given by

The power dissipated in the circuit shown in the figure is 30 Watts. The value of R is