Attempted
Correct
UnAttempted
Wrong
A 5 metre long wire is fixed to the ceiling. A weight of 10 kg is hung at the lower end and is 1 metre above the floor. The wire was elongated by 1 mm.The energy stored in the wire due to stretching is
W = 1⁄2 × F × l =1⁄2 mgl
=1⁄2 × 10 × 10 × 1 × 10-3 =0.05 joule
A material has poisson’s ratio 0.50. If a uniform rod of its uffers a longitudinal strain of 2× 10–3, then the percentage change in volume is
The diagram below shows the change in the length X of a thin uniform wire caused by the application of stress F at two different temperatures T1 and T2. The variation shown suggests that
When same stress is applied at two different temperatures, the increase in length is more at higher temperature. Thus T1 > T2.
If a rubber ball is taken at the depth of 200 m in a pool, its volume decreases by 0.1%. If the density of the water is 1 × 103kg/m3 and g = 10m/s2, then the volume elasticity in N/m2 will be
K is the force constant of a spring. The work done in increasing its extension from l1 to l2 will be
What per cent of length of wire increases by applying a stress of 1 kg weight/mm2 on it?(Y = 1× 1011N/m2 and 1 kg weight = 9.8 newton)
When a pressure of 100 atmosphere is applied on a spherical ball, then its volume reduces to 0.01%. The bulk modulus of the material of the rubber in dyne/cm2 is
On stretching a wire, the elastic energy stored per unit volume is
Energy stored per unit volume =1⁄2(F⁄A)(l⁄L)=-Fl⁄2AL
A metalic rod of length land cross-sectional area A is made of a material of Young modulus Y. If the rod is elongated by an amount y, then the work done is proportional to
A wire fixed at the upper end stretches by length l by applying a force F. The work done in stretching is