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If the gravitational force had varied as r–5/2 instead of r–2;the potential energy of a particle at a distance ‘r’from the centre of the earth would be proportional to
The radius of a planet is 1/4th of Re and its acc. due to gravity is 2g. What would be the value of escape velocity on the planet, if escape velocity on earth is ve.
What would be the length of a sec. pendulum at a planet(where acc. due to gravity is g/4) if it’s length on earth is l
If the mass of earth is eighty times the mass of a planet and diameter of the planet is one fourth that of earth, then acceleration due to gravity on the planet would be
The mass of the moon is 1/81 of earth’s mass and its radius 1/4 that of the earth. If the escape velocity from the earth’s surface is 11.2 km/sec, its value from the surface of the moon will be
A planet of mass 3 × 1029 gm moves around a star with aconstant speed of 2 × 106 ms–1 in a circle of radii 1.5 × 1014cm. The gravitational force exerted on the planet by the star is
Taking the gravitational potential at a point infinte distance awayas zero, the gravitational potential at a point A is –5 unit. If the gravitational potential at point infinite distance away is taken as + 10 units, the potential at point A is
Two planets of radii r1 and r2 are made from the same material. The ratio of the acceleration due to gravity g1/g2 at the surfaces of the two planets is
The weight of an object in the coal mine, sea level and at the top of the mountain,are respectively W1, W2 and W3 then
At the surface of earth, the value of g =9.8m/sec2. If we go towards the centre of earth or we go above the surface of earth, then in both the cases the value of g decreases.
Hence W1=mgmine, W2=mgsea level, W3=mgmoun
So W1< W2 > W3(g at the sea level = g at the suface of earth)
A planet moves around the sun. At a point P it is closest from the sun at a distance d1 and has a speed v1. At another point Q, when it is farthest from the sun at a distnace d2 its speed will be