If the gravitational force had varied as r–5/2 instead of r–2;the potential energy of a particle at a distance ‘r’from the centre of the earth would be proportional to
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The radius of a planet is 1/4th of Re and its acc. due to gravity is 2g. What would be the value of escape velocity on the planet, if escape velocity on earth is ve.
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What would be the length of a sec. pendulum at a planet(where acc. due to gravity is g/4) if it’s length on earth is l
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If the mass of earth is eighty times the mass of a planet and diameter of the planet is one fourth that of earth, then acceleration due to gravity on the planet would be
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The mass of the moon is 1/81 of earth’s mass and its radius 1/4 that of the earth. If the escape velocity from the earth’s surface is 11.2 km/sec, its value from the surface of the moon will be
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A planet of mass 3 × 1029 gm moves around a star with aconstant speed of 2 × 106 ms–1 in a circle of radii 1.5 × 1014cm. The gravitational force exerted on the planet by the star is
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Taking the gravitational potential at a point infinte distance awayas zero, the gravitational potential at a point A is –5 unit. If the gravitational potential at point infinite distance away is taken as + 10 units, the potential at point A is
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Two planets of radii r1 and r2 are made from the same material. The ratio of the acceleration due to gravity g1/g2 at the surfaces of the two planets is
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The weight of an object in the coal mine, sea level and at the top of the mountain,are respectively W1, W2 and W3 then
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At the surface of earth, the value of g =9.8m/sec2. If we go towards the centre of earth or we go above the surface of earth, then in both the cases the value of g decreases.
Hence W1=mgmine, W2=mgsea level, W3=mgmoun
So W1< W2 > W3(g at the sea level = g at the suface of earth)
A planet moves around the sun. At a point P it is closest from the sun at a distance d1 and has a speed v1. At another point Q, when it is farthest from the sun at a distnace d2 its speed will be
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