DIRECTIONS : Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-

(a)Statement -1 is false, Statement-2 is true

(b)Statement -1 is true, Statement-2 is true; Statement -2 is a correct explanation for Statement-1

(c)Statement -1 is true, Statement-2 is true; Statement -2 is not a correct explanation for Statement-1

(d)Statement -1 is true, Statement-2 is false

Statement-1 : For a charged particle moving from point P to point Q, the net work done by an electrostatic field on the particle is independent of the path connecting point P to point Q.

Statement-2 :The net work done by a conservative force on an object moving along a closed loop is zero.

View Ans & Explanation
(b)Statement -1 is true, Statement-2 is true; Statement -2 is a correct explanation for Statement-1

Statement 1 is true. Statement 2 is true and is the correct explanation of statement 1.

DIRECTIONS : Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-

(a)Statement -1 is false, Statement-2 is true

(b)Statement -1 is true, Statement-2 is true; Statement -2 is a correct explanation for Statement-1

(c)Statement -1 is true, Statement-2 is true; Statement -2 is not a correct explanation for Statement-1

(d)Statement -1 is true, Statement-2 is false

Statement 1 : For a non-uniformly charged thin circularring with net charge is zero,the electric field at any point on axis of the ring is zero.

Statement 2 :For a non-uniformly chargedthin circularring with net charge zero, the electric potential at each point on axis of the ring is zero.

View Ans & Explanation
(a)Statement -1 is false, Statement-2 is true

Fora non-uniformly charged thin circular ring with net zero charge, electric potential at each point on its axis is zero. Hence electric field at each point on its axis must be perpendicular to the axis. Therefore statement-1 is false and statement-2 is true.

DIRECTIONS : Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-

(a)Statement -1 is false, Statement-2 is true

(b)Statement -1 is true, Statement-2 is true; Statement -2 is a correct explanation for Statement-1

(c)Statement -1 is true, Statement-2 is true; Statement -2 is not a correct explanation for Statement-1

(d)Statement -1 is true, Statement-2 is false

Statement I : Two equipotential surfaces cannot cut each other.

Statement II : Two equipotential surfaces are parallel to each other.

View Ans & Explanation
(d)Statement -1 is true, Statement-2 is false

Two equipotential surfaces are not necessarily parallel to each other.

DIRECTIONS : Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-

(a)Statement -1 is false, Statement-2 is true

(b)Statement -1 is true, Statement-2 is true; Statement -2 is a correct explanation for Statement-1

(c)Statement -1 is true, Statement-2 is true; Statement -2 is not a correct explanation for Statement-1

(d)Statement -1 is true, Statement-2 is false

Statement 1 : Electric potential and electric potential energy are different quantities.

Statement 2 : For a system of positive test charge and point charge electric potential energy = electric potential.

View Ans & Explanation
(d)Statement -1 is true, Statement-2 is false

Potential and potential energy are different quantities and cannot be equated.

DIRECTIONS : Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-

(a)Statement -1 is false, Statement-2 is true

(b)Statement -1 is true, Statement-2 is true; Statement -2 is a correct explanation for Statement-1

(c)Statement -1 is true, Statement-2 is true; Statement -2 is not a correct explanation for Statement-1

(d)Statement -1 is true, Statement-2 is false

Statement 1 : Each of the plates of a parallel-plate capacitor is given equal positive charge Q. The charges on the facing surfaces will be same.

Statement 2 : A negative charge (–Q) will be induced on each of the facing surfaces.

View Ans & Explanation
(d)Statement -1 is true, Statement-2 is false

The charge on each of two facing surfaces will be zero.

A capacitor having capacitance 1µF with air, is filled with two dielectrics as shown. How many times capacitance will increase?

12
8
⁸⁄₃
3

Solution

A capacitor is charges by using a battery which is then disconnected. A dielectric slab in then introduced between the plates which results in the :

reduction of charge on the plates and increase of potential difference across the plates.
increase in the potential difference across the plates and reduction in stored energy but no change in the charge on the plates.
decrease in potential difference across the plates and reduction in stored energy but not change in the charge on the plates.
none of these

Solution

On an isolated capacitor charge remains constant.

A 10 volt battery is connected to three capacitors; C₁ =2µF, C₂= 3µF and C₃= 5m.F, as shown. The charges on the capacitors C₂, C₂ and C₃ respectively are :

2μC, 3μC, 5 μC
5 μC, 10 μC, 15μC
10 μC, 15 μC, 25μC
4μC, 6μC, 10 μC

Solution

Four point charges –Q, –q, 2q and 2Q are placed, one at each corner of the square. The relation between Q and q for which the potential at the centre of the square is zero is

Q= – q
Q= –¹⁄_q
Q= q
Q = ¹⁄_q

Solution

Four electric charges +q, +q, –q and – q are placed at the corners of a square of side 2L (see figure). The electric potential at point A, midway between the two charges +q and +q, is

\(\frac{1}{4\pi \epsilon _{0}}\frac{2q}{L}(1+\sqrt{5})\)
\(\frac{1}{4\pi \epsilon _{0}}\frac{2q}{L}(1+\frac{1}{\sqrt{5}})\)
\(\frac{1}{4\pi \epsilon _{0}}\frac{2q}{L}(1-\frac{1}{\sqrt{5}})\)
zero

Solution

A condenser of capacity C is charged to a potential difference of V₁. The plates of the condenser are then connected to an ideal inductor of inductance L. The current through the inductor when the potential difference across the condenser reduces to V₂ is

\(\left ( \frac{C(V_{1}^{2}-V_{2}^{2})}{L} \right )^{1/2}\)
\(\left ( \frac{C(V_{1}-V_{2})^{2}}{L} \right )^{1/2}\)
\(\frac{C(V_{1}^{2}-V_{2}^{2})^{2}}{L}\)
\(\frac{C(V_{1}-V_{2})^{2}}{L}\)

Solution

A series combination of n₁ capacitors, each of value C₁, is charged by a source of potential difference 4 V. When another parallel combination of n₂ capacitors, each of value C₂, is charged by a source of potential difference V, it has the same (total) energy stored in it, as the first combination has. The value of C₂, in terms of C₁, is then

\(\frac{2C_{1}}{n_{1}n_{2}}\)
\(16\frac{n_{2}}{n_{1}}C_{1}\)
\(2\frac{n_{2}}{n_{1}}C_{1}\)
\(\frac{16C_{1}}{n_{1}n_{2}}\)

Solution

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