The maximum kinetic energy (E_max) of photoelectrons emitted in a photoelectric cell varies with frequency (v) as shown in the graph. The slope of the graph is equal to

charge of the electron
^e⁄_m of the electron
work function of the emitter
Plank’s constant

Einstein’s photoelectric equation is E_k = hv – φ. In this equation E_k refers to

kinetic energy of all the emitted electrons
mean kinetic energy of emitted electrons
maximum kinetic energy of emitted electrons
minimum kinetic energy of emitted electrons

The maximum velocity of an electron emitted by light of wavelength λ incident on the surface of a metal of work-function φ is

\(\sqrt{\frac{2(hc+\lambda \phi )}{m\lambda }}\)
\(\frac{2(hc+\lambda \phi )}{m\lambda }\)
\(\sqrt{\frac{2(hc-\lambda \phi )}{m\lambda }}\)
\frac{2(hc-\lambda \phi )}{m\lambda }

Solution

The velocity of a body of rest mass m_o is ^√3⁄₂c (where c is the velocity of light in vacuum). The mass of this body is:

(^√3⁄₂)m_o
(¹⁄₂)m_o
3m_o
2m_o

Solution

4eV is the energy of incident photon and the work function is 2eV. The stopping potential will be

2V
4V
6V
2√2V

Solution

Einstein’s work on photoelectric effect provided support for the equation

E = hv
E = mc²
\(E=\frac{-Rhc}{n^{2}}\)
K.E = ¹⁄₂ mv²

Solution

Einstein’s photo electric effect & compton effect established particle nature of light. These effects can be explained only, when we assume that the light has particle nature (To explain, Interference & Diffraction the light must have wave nature. It means that light has both particle and wave nature, so it is called dual nature of light)

The photoelectric work function for a metal surface is 4.125 eV. The cut-off wavelength for this surface is

4125 Å
3000 Å
6000 Å
2062 Å

Solution

A particle with rest mass m₀ is moving with speed of light c.The de-B roglie wavelength associated with it will be

α
zero
m₀c/h
hv/m₀c

Solution

A proton and α-particle are accelerated through the same potential difference. The ratio of their de-B roglie wavelength will be

1 : 1
1 : 2
2 : 1
2√2 : 1

Solution

In a photoelectric experiment the stopping potential for the incident light of wavelength 4000 Å is 2 volt. If the wave length be changed to 3000 Å, the stopping potential will be

2 V
zero
less than 2 V
more than 2 V

Solution

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