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In the network shown, each resistance is equal to R. The equivalent resistance between adjacent corners A and D is

R
²⁄₃R
³⁄₇R
⁸⁄₁₅R

Solution

In the circuit shown, the internal resistance of the cell is negligible. The steady state current in the 2Ω resistor is

0.6 A
0.9 A
1.2 A
1.5 A

Solution

The numerical value of charge on either plate of capacitor C shown in figure is

C E
\(\frac{CER_{1}}{R_{1}+r}\)
\(\frac{CER_{2}}{R_{2}+r}\)
\(\frac{CER_{1}}{R_{2}+r}\)

Solution

Twelve indentical resistors each of value 1 Ω are connected as shown. Net resistance between C and D (R)is

R = ⁷⁄₆ Ω
R = ⁴⁄₃ Ω
R = 1 Ω
R = ³⁄₄ Ω

Solution

Current in arm AE and FB is zero.So,

There is an infinite wire grid with cells in the form of equilateral triangles. The resistance of each wire between neighbouring joint connections is R₀. The net resistance of the whole grid between the points A and B as shown is

R₀
^R₀⁄₂
^R₀⁄₃
^R₀⁄₄

Solution

A battery of e.m.f E and internal resistance r is connected to a variable resistor R as shown. Which one of the following is true ?

A. Potential difference across the terminals of the battery is maximum where R =r

B. Power delivered to resistor is maximum when R = r

C. Current in the circuit is maximum when R = r

D. Current in the circuit is maximum when R >> r

Solution

B,C

Twelve resistors each of resistance 16Ω are connected in the circuit as shown. The net resistance between AB is

Solution

Determine the current in 2Ω resistor.

1 A
1.5 A
0.9 A
0.6 A

Solution

The equivalent resistance between A and B is

^8R⁄₅
^5R⁄₈
^3R⁄₈
^7R⁄₈

Solution

The equivalent circuit can be redrawn as

Three resistances are connected to forma T-shape as shown in the figure.Then the current in the 4K resistor is:

0.93mA
1.42mA
2.5mA
1.57mA

Solution

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