Direction: Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-
(a) Statement -1 is true, Statement-2 is true;Statement -2 is a correct explanation for Statement-1
(b)Statement -1 is true, Statement-2 is true; Statement -2 is not a correct explanation for Statement-1
(c)Statement -1 is true, Statement-2 is false
(d)Statement -1 is false, Statement-2 is true
Statement 2:The current flows towards the point of the higher potential, as it does in such a circuit from the negative to the positive terminal.
- View Ans & Explanation
(c)Statement -1 is true, Statement-2 is false
Positive terminal of a battery is point of highest potential and current flows from highest to lowest potential i.e. from +ve to –ve potential.
Direction: Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-
(a) Statement -1 is true, Statement-2 is true;Statement -2 is a correct explanation for Statement-1
(b)Statement -1 is true, Statement-2 is true; Statement -2 is not a correct explanation for Statement-1
(c)Statement -1 is true, Statement-2 is false
(d)Statement -1 is false, Statement-2 is true
Statement 2 : Light produced is same from same power.
- View Ans & Explanation
(c)Statement -1 is true, Statement-2 is false
In tube light majority portion of radiation comes under visible region while bulb radiation consists of visible,ultraviolet, infrared radiation giving less visible part.
Direction: Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-
(a) Statement -1 is true, Statement-2 is true;Statement -2 is a correct explanation for Statement-1
(b)Statement -1 is true, Statement-2 is true; Statement -2 is not a correct explanation for Statement-1
(c)Statement -1 is true, Statement-2 is false
(d)Statement -1 is false, Statement-2 is true
Statement 2 : Resistance of bulb is in versely proportional to rated power.
- View Ans & Explanation
(a) Statement -1 is true, Statement-2 is true;Statement -2 is a correct explanation for Statement-1
Direction: Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-
(a) Statement -1 is true, Statement-2 is true;Statement -2 is a correct explanation for Statement-1
(b)Statement -1 is true, Statement-2 is true; Statement -2 is not a correct explanation for Statement-1
(c)Statement -1 is true, Statement-2 is false
(d)Statement -1 is false, Statement-2 is true
Statement 2 : At high voltage supply power losses are less
- View Ans & Explanation
(a) Statement -1 is true, Statement-2 is true;Statement -2 is a correct explanation for Statement-1
Direction: Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-
(a) Statement -1 is true, Statement-2 is true;Statement -2 is a correct explanation for Statement-1
(b)Statement -1 is true, Statement-2 is true; Statement -2 is not a correct explanation for Statement-1
(c)Statement -1 is true, Statement-2 is false
(d)Statement -1 is false, Statement-2 is true
Statement 2 : Glow (Power) which is directly proportional to square of current.
- View Ans & Explanation
(a) Statement -1 is true, Statement-2 is true;Statement -2 is a correct explanation for Statement-1
Direction: Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-
(a) Statement -1 is true, Statement-2 is true;Statement -2 is a correct explanation for Statement-1
(b)Statement -1 is true, Statement-2 is true; Statement -2 is not a correct explanation for Statement-1
(c)Statement -1 is true, Statement-2 is false
(d)Statement -1 is false, Statement-2 is true
Statement 2 : A potentiometer draws no current while measuring emf of a cell.
- View Ans & Explanation
(d)Statement -1 is false, Statement-2 is true
Potentiometer is preferred for measurement of emf of cell. Potentiometer draws no current from cell while voltmeter draws some current, therefore emf measured by voltmeter is slightly less than actual value of emf of cell. Further the potentiometer is used with a galvanometer which is set to null reading when the experiment is performed. The method of null reading avoids many errors.
Direction: Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-
(a) Statement -1 is true, Statement-2 is true;Statement -2 is a correct explanation for Statement-1
(b)Statement -1 is true, Statement-2 is true; Statement -2 is not a correct explanation for Statement-1
(c)Statement -1 is true, Statement-2 is false
(d)Statement -1 is false, Statement-2 is true
Statement 2 : The drift velocity of electron in presence of electric field decreases.
- View Ans & Explanation
(c)Statement -1 is true, Statement-2 is false
Before the presence of electric field,the free electrons move randomly in the conductor, so their drift velocity is zero and therefore there is no current in the conductor.In the presence of electric field, each electron in the conductor experience a force in a direction opposite to the electric field. Now the free electrons are accelerated from negative and to the positive end of the conductor and hence a current starts to flow from the conductor.
Direction: Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer(ONLY ONE option is correct ) from the following-
(a) Statement -1 is true, Statement-2 is true;Statement -2 is a correct explanation for Statement-1
(b)Statement -1 is true, Statement-2 is true; Statement -2 is not a correct explanation for Statement-1
(c)Statement -1 is true, Statement-2 is false
(d)Statement -1 is false, Statement-2 is true
Statement 2 : In the situation of a short-circuit,the current is zero
- View Ans & Explanation
(c)Statement -1 is true, Statement-2 is false
In the case of a short-circuited battery, the current
\(I=\frac{E(emf\, of\, the\, battery)}{r(internal\, resistance)}\neq 0\)Terminal voltage V = IR = I (i) = I (0)= 0
where R = external r esistance =0
A galvanometer having a resistance of 8 Ω is shunted by a wire of resistance 2 Ω. If the total current is 1 A, the part of it passing through the shunt will he
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Solution
When the current i is flowing through a conductor, the drift velocity is v. If 2i current is flowed through the same metal but having double the area of cross-section,then the drift velocity will be
In the circuit shown the value of I in ampere is
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Solution
Five equal resistors when connected in series dissipated 5 watt power. If they are connected in parallel, the power dissipated will be
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Solution
A nichrome wire 1m long and 1 mm2 in cross-sectional area draws 4 ampere at 2 volt. The resistivity of nichrome is
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Solution
Every atom makes one free electron in copper. If 1.1 ampere current is flowing in the wire of copper having 1 mm diameter,then the drift velocity (approx) will be(density of copper= 9 × 103 kg m-3 and atomic weight of copper =63)
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Solution