NEET

In an A.C. circuit with phase voltage V and current I, the power dissipated is

VI
V²I
VI²
V²I²

The ratio of mean value over half cycle to r.m.s. value of A.C. is

2: π
2√2 : π
√2 : π
√2 : 1

Solution

A bulb and a capacitor are connected in series to a source of alternating current. If its frequency is increased, while keeping the voltage of the source constant, then bulb will

give more intense light
give less intense light
give light of same intensity before
stop radiating light

An AC voltage source has an output of V= 200 sin 2πft.This source is connected to a 100 Ω resistor. RMS currentin the resistance is

1.41 A
2.41 A
3.41 A
0.71 A

Fleming’s left and right hand rules are used in

DC motor and AC generator
DC generator and AC motor
DC motor and DC generator
Both rules are same, any one can be used

The impedance in a circuit containing a resistance of 1 Ω and an inductance of 0.1 H in series, for AC of 50 Hz, is

100√10Ω
10√10Ω
100Ω
√10Ω

An LCR series circuit, connected to a source E, is at resonance. Then the voltage across

R is zero
R equals applied voltage
C is zero
L equals applied voltage

The frequency of A.C. mains in India is

30 c/s
50 c/s
60 c/s
120 c/s

Solution

In an a.c. circuit, the r.m.s. value of current, I_rms is related to the peak current, I₀ by the relation

\(I_{rms}=\sqrt{2}I_{0}\)
\(I_{rms}=\pi I_{0}\)
\(I_{rms}=\frac{1}{\pi} I_{0}\)
\(I_{rms}=\frac{1}{\sqrt{2}} I_{0}\)

The time constant of C–R circuit is

1/CR
C/R
C R
R/C

UnAttempted

0

Attempted

0

Correct

0

Wrong

0

Complete

Attempted

Correct

UnAttempted

Wrong